For weak electrolytes, why is $\Lambda_0$ determined indirectly (via Kohlrausch's law from strong electrolyte data) rather than by extrapolation?
AWeak electrolytes have no $\Lambda_0$
BWeak electrolytes don't dissociate at all
C$\Lambda$ vs $\sqrt c$ is not linear for weak electrolytes, so extrapolation is unreliable
DStrong electrolytes are easier to handle
Answer & Solution
Correct answer: C. $\Lambda$ vs $\sqrt c$ is not linear for weak electrolytes, so extrapolation is unreliable
For weak electrolytes, dissociation increases steeply on dilution and $\Lambda$ vs $\sqrt c$ is curved (not linear) — extrapolation to infinite dilution is unreliable. Kohlrausch's additivity rule provides a workaround using strong electrolytes whose $\Lambda_0$ can be obtained by extrapolation.
Related questions
For an electrochemical cell operating spontaneously, ΔG° is related to E°_cell byWhich of the following statements about electrode potentials is INCORRECT?The overall cell reaction of the lead storage battery on discharge isThe primary cell that cannot be reused after its EMF drops to zero is exemplified byRusting of iron requires which two chemicals in contact with the metal?Fuel cells directly convertThe specific conductivity of a 0.1 M KCl solution is 1.29 × 10⁻² S/cm. The molar conductivMolar conductivity of a strong electrolyte at concentration c is related to its limiting v