For a BJT in active mode with collector current IC = β·IB + (β+1)·ICBO, the relation between α (CB) and β (CE) is which?
Aα = β² and β = √α
Bα = β·(β+1) and β = α-1
Cα = 1/β always and β = α·VT
Dα = β/(β+1) and β = α/(1-α)
Answer & Solution
Correct answer: D. α = β/(β+1) and β = α/(1-α)
BJT identities: α = IC/IE (common-base), β = IC/IB (common-emitter). KCL at emitter: IE = IB+IC ⟹ algebra ⟹ α = β/(β+1).
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