alleryThe relationship between $\Delta G^\circ$ and the equilibrium constant $K$ for a chemical reaction is:
A$\Delta G^\circ = -R T K$
B$\Delta G^\circ = R T / \ln K$
C$\Delta G^\circ = -R T \ln K$
D$\Delta G^\circ = R T \ln K$
Answer & Solution
Correct answer: C. $\Delta G^\circ = -R T \ln K$
At equilibrium $\Delta G = 0 = \Delta G^\circ + R T \ln Q$ with $Q = K$, so $\Delta G^\circ = -R T \ln K$.
A negative $\Delta G^\circ$ corresponds to $K > 1$ (product-favoured equilibrium)
a positive $\Delta G^\circ$ to $K < 1$ (reactant-favoured)
$\Delta G^\circ = 0$ to $K = 1$.
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