Start learning →

The relation between $\Delta H$ and $\Delta U$ for a reaction involving gases is:

A$\Delta H = \Delta U \cdot \Delta n_g R T$
B$\Delta H = \Delta U - \Delta n_g R T$
C$\Delta H = \Delta U + \Delta n_g R T$
D$\Delta H = \Delta U / \Delta n_g$
Answer & Solution
Correct answer: C. $\Delta H = \Delta U + \Delta n_g R T$
From the definition $H = U + pV$ and the ideal-gas relation $pV = n_g R T$, $\Delta H = \Delta U + \Delta(pV) = \Delta U + \Delta n_g R T$ at constant $T$, where $\Delta n_g$ is (moles of gaseous products) $-$ (moles of gaseous reactants). For reactions with $\Delta n_g = 0$, $\Delta H = \Delta U$.
Practise this question with Quill — JEE Advanced →

Keep practising Unit 6A1: Heat Transfer and Calorimetry

Browse all Unit 6A1: Heat Transfer and Calorimetry questions for JEE Advanced, or explore more Chemistry topics.

Start a Unit 6A1: Heat Transfer and Calorimetry lesson →