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The roots of a quadratic equation $ax^2+bx+c=0$ are given by the quadratic formula:
A$x = \dfrac{-b \pm \sqrt{4ac-b^2}}{2a}$
B$x = \dfrac{-b \pm \sqrt{b^2-4ac}}{2a}$
C$x = \dfrac{b \pm \sqrt{b^2-4ac}}{2a}$
D$x = \dfrac{-b \pm \sqrt{b^2+4ac}}{2a}$
Answer & Solution
Correct answer: B. $x = \dfrac{-b \pm \sqrt{b^2-4ac}}{2a}$
x = (−b ± √(b²−4ac)) / 2a is the quadratic formula.
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