For an ideal gas, the relationship between $C_p$ and $C_v$ is (Mayer's relation):
A$C_p - C_v = R$
B$C_p + C_v = R$
C$C_p = C_v$
D$C_p \cdot C_v = R$
Answer & Solution
Correct answer: A. $C_p - C_v = R$
Mayer's relation: $C_p - C_v = R$, where $R$ is the universal gas constant.
**Derivation:** at constant volume, heat $Q = nC_v\Delta T$ all becomes internal energy.
At constant pressure, $Q = nC_p\Delta T$, but some heat does PdV work against the surroundings
that work equals $nR\Delta T$.
Setting $nC_p\Delta T = nC_v\Delta T + nR\Delta T$ gives $C_p - C_v = R$.
Monoatomic: $C_v = \dfrac{3}{2}R$, $C_p = \dfrac{5}{2}R$, $\gamma = 5/3$.
Diatomic: $C_v = \dfrac{5}{2}R$, $C_p = \dfrac{7}{2}R$, $\gamma = 7/5$.
The $R$ gap is always there because of that PdV work.
Keep practising Kinetic Theory & Oscillations
Browse all Kinetic Theory & Oscillations questions for JEE Advanced, or explore more Physics topics.