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![](https://qallery.app/diagrams/v2_electro_seed_1/img-1.jpeg) In the Daniell cell shown, which metal acts as the **anode** (site of oxidation)?

AZinc (Zn)
BIron (Fe)
CCopper (Cu)
DSilver (Ag)
Answer & Solution
Correct answer: A. Zinc (Zn)
The Daniell cell has Zn dipped in $\mathrm{ZnSO_4}$ and Cu dipped in $\mathrm{CuSO_4}$, connected by a salt bridge. Zn has a lower (more negative) standard reduction potential than Cu. So Zn loses electrons more readily: $\mathrm{Zn} \to \mathrm{Zn^{2+}} + 2e^-$. The Zn electrode is the **anode** (oxidation). Meanwhile $\mathrm{Cu^{2+}}$ ions accept those electrons at the copper electrode: $\mathrm{Cu^{2+}} + 2e^- \to \mathrm{Cu}$. The Cu electrode is the **cathode** (reduction). Mnemonic: **a**node $\to$ **a**node where **a**nions go / **a**node has **a**lphabet 'a' before cathode 'c'.
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