Monochromatic light of wavelength $\lambda$ passes through a single slit of width $a$. The angular position $\theta$ of the **first** diffraction minimum (on either side of the central maximum) is given by:
A$\sin\theta = \dfrac{\lambda}{2a}$
B$\sin\theta = \dfrac{\lambda}{a}$
C$\sin\theta = \dfrac{2\lambda}{a}$
D$\sin\theta = \dfrac{3\lambda}{2a}$
Answer & Solution
Correct answer: B. $\sin\theta = \dfrac{\lambda}{a}$
Single-slit diffraction condition for the $n$-th dark fringe: $a \sin\theta = n\lambda$ where $n = \pm 1, \pm 2, \ldots$ (the central maximum sits at $\theta = 0$).
For the **first** minimum, $n = 1$, giving $\sin\theta = \dfrac{\lambda}{a}$.
A common trap is to confuse single-slit diffraction with double-slit interference: in double-slit experiments the $n$-th *bright* fringe sits at $d \sin\theta = n\lambda$, but here we are after the *dark* fringes of a single slit.
Related questions
Blue sky seen through a rotating polaroid rises and falls in brightness. Sky light is:Two polaroids are set crossed. The light passing through both is:Ordinary lamp light passes through one polaroid. Its intensity drops to:Wiggle a string up and down and a wave runs along it. The displacement is at right angles The rainbow of colours you see on a CD comes from:Diffraction is shown by:Near the edge of a shadow you see alternate dark and bright bands. This is:In Young's pattern, consecutive bright fringes are: