A light ray travels from glass ($\mu = 1.5$) to air. The critical angle for total internal reflection at the glass–air interface is approximately:
A$30°$
B$42°$
C$60°$
D$90°$
Answer & Solution
Correct answer: B. $42°$
**Critical angle formula** (denser → rarer): $\sin C = \dfrac{\mu_{\text{rarer}}}{\mu_{\text{denser}}} = \dfrac{1}{\mu_{\text{denser}}} = \dfrac{1}{1.5} \approx 0.667$.
$C = \sin^{-1}(0.667) \approx 41.8° \approx 42°$.
**Why option C (60°) is tempting.** Some recall $\sin^{-1}(0.866) = 60°$ — but that's $\mu = 1/0.866 \approx 1.15$, not $1.5$. A useful sanity check: as $\mu$ rises, the critical angle drops (denser glass holds light in more aggressively). Diamond's $C \approx 24°$ — that's why it sparkles.
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