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![](https://qallery.app/diagrams/v2_rayoptics_seed_1/img-16.jpeg) A monochromatic light ray passes through a prism of refracting angle $A = 60°$ at minimum deviation. If the angle of minimum deviation is $\delta_m = 30°$, find the refractive index of the prism material.

A$1.00$
B$1.33$
C$\sqrt{2}$
D$\sqrt{3}$
Answer & Solution
Correct answer: C. $\sqrt{2}$
**Prism formula at minimum deviation:** $$\mu = \dfrac{\sin\!\left(\dfrac{A + \delta_m}{2}\right)}{\sin\!\left(\dfrac{A}{2}\right)}$$ **Substitute.** $\dfrac{A + \delta_m}{2} = \dfrac{60 + 30}{2} = 45°$ and $\dfrac{A}{2} = 30°$. $$\mu = \dfrac{\sin 45°}{\sin 30°} = \dfrac{\sqrt{2}/2}{1/2} = \sqrt{2} \approx 1.414$$ Option B (1.33) is water's refractive index — a tempting wrong pick if you guess instead of computing.
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