alleryEvaluate $\displaystyle\lim_{x \to 2} \dfrac{x^2 - 4}{x - 2}$.
AThe limit does not exist
B$4$
C$2$
D$0$
Answer & Solution
Correct answer: B. $4$
Factor the numerator: $x^2 - 4 = (x-2)(x+2)$. Cancelling, $\dfrac{(x-2)(x+2)}{x-2} = x + 2$ for $x \neq 2$. Limit = $4$.
Option D is the trap if you stop at the $0/0$ form without factoring.
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