Home › JEE Main › Mathematics › Limits and Derivatives › The limit $\lim_{x\to 2}(x^2 + 3x - 1)$ equals:
The limit $\lim_{x\to 2}(x^2 + 3x - 1)$ equals:
A$5$, ignoring the constant in the polynomial on the chart
B$9$, by substitution since the polynomial is continuous here
C$0$, since the limit at a point is always zero on the chart
D$3$, taking only the linear term in the polynomial here
Answer & Solution
Correct answer: B. $9$, by substitution since the polynomial is continuous here
Polynomials are continuous; $\lim = (2)^2 + 3(2) - 1 = 4 + 6 - 1 = 9$.
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