alleryStart learning →For a thin sphere under internal pressure p:
Aσ = pd/t
Bσ = pd/(4t) (uniform in all directions, by symmetry)
CRandom
Dσ = pd/(2t)
Answer & Solution
Correct answer: B. σ = pd/(4t) (uniform in all directions, by symmetry)
**Thin sphere:** only one stress component due to symmetry.
σ = pd/(4t) in any direction.
Half the cylinder hoop stress.
Spheres are more efficient pressure vessels than cylinders for same wall thickness.
LPG tanks, pressure storage vessels often spherical or hemispherical-ended cylinders.
Keep practising Strength of Materials
Browse all Strength of Materials questions for B.Tech Civil, or explore more Civil Engineering topics.
Related questions
Modulus of elasticity for concrete (per IS 456):Yield strength of structural mild steel (IS 226):For thin cylinder under internal pressure p (diameter d, thickness t):For pure shear (σ_x = σ_y = 0, τ_xy = τ), principal stresses are:Maximum shear stress occurs on planes oriented at ___ to principal planes:Principal planes are characterized by:Slenderness ratio of a column is:Effective length L_e for fixed-free (cantilever) column is: