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For a thin sphere under internal pressure p:
Aσ = pd/t
Bσ = pd/(4t) (uniform in all directions, by symmetry)
CRandom
Dσ = pd/(2t)
Answer & Solution
Correct answer: B. σ = pd/(4t) (uniform in all directions, by symmetry)
Thin sphere: only one stress component due to symmetry. σ = pd/(4t) in any direction. Half the cylinder hoop stress. Spheres are more efficient pressure vessels than cylinders for same wall thickness. LPG tanks, pressure storage vessels often spherical or hemispherical-ended cylinders.
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