alleryFor hyperbola x²/25 - y²/144 = 1, find length of conjugate axis:
A10
B24 (= 2b, with b² = 144 → b = 12)
Csqrt(169) = 13
D144
Answer & Solution
Correct answer: B. 24 (= 2b, with b² = 144 → b = 12)
Transverse axis: 2a = 10. Conjugate axis: 2b = 24 (b² = 144, b = 12). Foci at (±13, 0). e = 13/5.
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