Home › CBSE Class 11 › Mathematics › Conic Sections › For a general 2nd-degree equation Ax² + Bxy + Cy…
For a general 2nd-degree equation Ax² + Bxy + Cy² + Dx + Ey + F = 0, the curve is a PARABOLA when:
A$B^2 - 4AC < 0$ (an ellipse case)
B$B^2 - 4AC > 0$ (a hyperbola case)
C$B^2 - 4AC = 0$ (a parabola case)
D$A = B = C$ (no clear classification)
Answer & Solution
Correct answer: C. $B^2 - 4AC = 0$ (a parabola case)
Discriminant Δ = B² − 4AC. Δ = 0 → parabola. Δ < 0 → ellipse (circle if A = C, B = 0). Δ > 0 → hyperbola. Degenerate cases give lines or points.
Related questions
The latus rectum of an ellipse is perpendicular to the:The latus rectum of a parabola passes through the:A hyperbola is the set of points where the difference of two distances is:The eccentricity of an ellipse is defined as a ratio of two:The two fixed points used to define an ellipse are called the:An ellipse is the set of points where the sum of two distances is:The fixed line used to define a parabola is called the:A parabola is the set of points equidistant from a fixed line and a fixed: