Equation of circle passing through origin, (a, 0), (0, b):
Ax² + y² = a + b
BOther
Cx² + y² - ax - by = 0 (using general second-degree fits)
Dx² + y² = ab
Answer & Solution
Correct answer: C. x² + y² - ax - by = 0 (using general second-degree fits)
General circle x² + y² + 2gx + 2fy + c = 0. Through (0,0): c = 0. Through (a,0): a² + 2ag = 0 → g = -a/2. Through (0,b): b² + 2bf = 0 → f = -b/2. So x² + y² - ax - by = 0.
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