alleryEquation of circle passing through origin, (a, 0), (0, b):
Ax² + y² = a + b
BOther
Cx² + y² - ax - by = 0 (using general second-degree fits)
Dx² + y² = ab
Answer & Solution
Correct answer: C. x² + y² - ax - by = 0 (using general second-degree fits)
General circle x² + y² + 2gx + 2fy + c = 0. Through (0,0): c = 0. Through (a,0): a² + 2ag = 0
→ g = -a/2. Through (0,b): b² + 2bf = 0
→ f = -b/2. So x² + y² - ax - by = 0.
Keep practising Straight Lines and Conic Sections
Browse all Straight Lines and Conic Sections questions for GRE, or explore more Mathematics topics.
Related questions
The line 3x − 4y + 12 = 0 cuts the y-axis atThe intercept form of the equation of a line making intercepts a and b on the x- and y-axeThe distance between the parallel lines 3x + 4y = 7 and 3x + 4y = 12 isThe angle θ between two lines with slopes m₁ and m₂ satisfiesThe distance from the point (0, 0) to the line 3x + 4y − 25 = 0 isEquation of the line passing through (3, 4) and parallel to the line 2x − 3y = 5 isThe equation of the line passing through (2, −1) with slope 3 isThe slope-intercept form y = mx + c of the line 3x + 4y = 8 gives a slope of