Conjugate hyperbola of x²/a² - y²/b² = 1:
Ax²/a² - y²/b² = -1 (equivalent to conjugate)
BNo conjugate
Cy²/b² - x²/a² = 1 (axes swapped, transverse axis along y)
DSame
Answer & Solution
Correct answer: A. x²/a² - y²/b² = -1 (equivalent to conjugate)
Conjugate hyperbola: x²/a² - y²/b² = -1, equivalently y²/b² - x²/a² = 1. Shares asymptotes with original but oriented along y-axis. Eccentricities are related: 1/e² + 1/e'² = 1.
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