alleryStandard ellipse x²/a² + y²/b² = 1 (a > b) has eccentricity:
Ae = sqrt(1 - b²/a²) (0 < e < 1)
Be > 1
Ce = 1
De = 0
Answer & Solution
Correct answer: A. e = sqrt(1 - b²/a²) (0 < e < 1)
e = sqrt(1 - b²/a²).
For circle (a = b): e = 0. For ellipse: 0 < e < 1. Foci at (±ae, 0).
As e → 1, ellipse becomes more elongated.
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