allery3D analog of Pythagoras: for a box with sides a, b, c, the body diagonal is:
Aa + b + c
B2(a + b + c)
Csqrt(a² + b² + c²)
Dabc
Answer & Solution
Correct answer: C. sqrt(a² + b² + c²)
**Body diagonal of rectangular box:** d = sqrt(a² + b² + c²).
For cube (a=b=c): d = a sqrt(3).
Keep practising Unit 8A: Areas Between Curves
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