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3D analog of Pythagoras: for a box with sides a, b, c, the body diagonal is:
Aa + b + c
B2(a + b + c)
Csqrt(a² + b² + c²)
Dabc
Answer & Solution
Correct answer: C. sqrt(a² + b² + c²)
Body diagonal of rectangular box: d = sqrt(a² + b² + c²). For cube (a=b=c): d = a sqrt(3).
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