Start learning →

Equation of straight line passing through two points A(1,2,3) and B(4,5,6):

A(x-1)/3 = (y-2)/3 = (z-3)/3 (direction = B-A = (3,3,3))
Bx = y = z
C(x-1)/4 = (y-2)/5 = (z-3)/6
Dx + y + z = 6
Answer & Solution
Correct answer: A. (x-1)/3 = (y-2)/3 = (z-3)/3 (direction = B-A = (3,3,3))
Direction = B - A = (3, 3, 3) or any scalar multiple (1, 1, 1). Through A(1,2,3): (x-1)/1 = (y-2)/1 = (z-3)/1, equivalently (x-1)/3 = (y-2)/3 = (z-3)/3.
Practise this question with Quill — AP Calculus AB →

Keep practising Unit 8A: Areas Between Curves

Browse all Unit 8A: Areas Between Curves questions for AP Calculus AB, or explore more Mathematics topics.

Start a Unit 8A: Areas Between Curves lesson →