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Plane passing through origin and perpendicular to line (x-1)/2 = (y-2)/3 = (z-3)/-1:
A2x + 3y - z = 0 (normal = line direction)
Bx + y + z = 0
Cx - y - z = 0
Dz = 0
Answer & Solution
Correct answer: A. 2x + 3y - z = 0 (normal = line direction)
Direction of line = (2, 3, -1). Plane perpendicular to line has this as normal. Through origin: 2x + 3y - z = 0.
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