alleryBy chain rule, d/dx [sin(x²)] =
Acos(2x)
B2x cos(x²)
Csin(2x)
Dcos(x²)
Answer & Solution
Correct answer: B. 2x cos(x²)
**Chain rule:** d/dx [f(g(x))] = f'(g(x)) × g'(x).
With f = sin, g = x²: derivative = cos(x²) × 2x = 2x cos(x²).
Keep practising Unit 1B1: Limit Concepts and Graphical Limits
Browse all Unit 1B1: Limit Concepts and Graphical Limits questions for AP Calculus AB, or explore more Mathematics topics.
Related questions
Which of the following is a rational number?Which statement is true for a polynomial of degree $n$?If $(d,m,n)$ are direction cosines of a line, which relation must hold?If $A$ is a square matrix with $|A| = 3$ and order $n = 3$, then $|\operatorname{adj}(A)|$For a non-singular $n \times n$ matrix $A$, the relation between $\det(\operatorname{adj} A square matrix $A$ is **invertible** if and only if:If $A$ and $B$ are matrices for which $AB$ is defined, then $(AB)'$ equals:The diagonal entries of any skew-symmetric matrix are: