lim_(x→0) (e^x - 1)/x =
Ae
BIndeterminate
C1
D0
Answer & Solution
Correct answer: C. 1
By l'Hôpital or Taylor: e^x ≈ 1 + x + x²/2 + ... So (e^x - 1)/x ≈ 1 + x/2 + ... → 1 as x → 0. (Equivalent to d/dx(e^x) at x = 0 = e⁰ = 1.)
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