Locus of z satisfying |z - 1| = |z - i|:
AImaginary axis
BReal axis
CCircle around (0, 0)
DPerpendicular bisector of segment from (1, 0) to (0, 1)
Answer & Solution
Correct answer: D. Perpendicular bisector of segment from (1, 0) to (0, 1)
|z - z1| = |z - z2| means z is equidistant from z1 and z2. Locus = perpendicular bisector of segment from z1 to z2. Here z1 = 1 (point (1,0)) and z2 = i (point (0,1)). Bisector is y = x line.
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