The modulus of $z = 5 + 12i$ is:
A$13$, since $|z| = \sqrt{25 + 144} = \sqrt{169} = 13$
B$17$, the simple sum of real and imaginary parts
C$5$, equal only to the real part of the number here
D$169$, the squared modulus reported as the modulus
Answer & Solution
Correct answer: A. $13$, since $|z| = \sqrt{25 + 144} = \sqrt{169} = 13$
$|z| = \sqrt{5^2 + 12^2} = \sqrt{169} = 13$.
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