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Compute (1 + i)⁸:

A-16i
B16
C16i
D-16
Answer & Solution
Correct answer: B. 16
(1+i) = √2 cis(π/4). **So (1+i)⁸ = (√2)⁸ × cis(8π/4) = 16 × cis(2π) = 16 × 1 = 16.**
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