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Compute (2 + i)(3 - 2i):

A6 - 2i
B8 - i
C6 - i
D8 + i
Answer & Solution
Correct answer: B. 8 - i
We have (2+i)(3-2i) = 6 - 4i + 3i - 2i². That is (2+i)(3-2i) = 6 - i - 2(-1). That is (2+i)(3-2i) = 6 - i + 2. So (2+i)(3-2i) = 8 - i.
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