The general solution of cos x = 0 is:
Ax = nπ
Bx = (n + 1) π/4
Cx = 2nπ
Dx = (2n + 1) π/2, n ∈ Z
Answer & Solution
Correct answer: D. x = (2n + 1) π/2, n ∈ Z
1. cos x = 0 at x = π/2, 3π/2, 5π/2, ... — odd multiples of π/2.
2. General form: x = (2n + 1) π/2, n ∈ Z.
_Source: NCERT Class 11 Maths Ch 3 §3.5 General Solutions_
Related questions
If cos θ = −1/2 and θ ∈ (π, 3π/2), then θ equals:tan(45° + θ) · tan(45° − θ) is equal to:sin 75° equals:By the law of sines in a triangle, a / sin A is equal to:The general solution of sin x = 0 is:If sin θ = 3/5 and θ is acute, then cos θ equals:The angle in radians for 120° is:The principal value of the range of f(x) = sin x is: