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Glycolysis begins with one glucose molecule and ends with two molecules of:
ALactate
BPyruvate
CEthanol
DCitrate
Answer & Solution
Correct answer: B. Pyruvate
1. Glucose is a six-carbon ring-shaped sugar.
2. Glycolysis splits that ring evenly in two.
3. Glycolysis begins with the six carbon ring-shaped structure of a single glucose molecule and ends with two molecules of a three-carbon keto acid called pyruvate.
4. Lactate and ethanol appear only later, in fermentation.
_Source: OpenStax Biology for AP(R) Courses (CC BY 4.0), Ch 7 'Cellular Respiration', sections 7.1-7.7_
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