For methanol reacting with ethyl acetate, the rate law is rate = k[CH3OH]. What are the orders in ethyl acetate and overall?
AFirst order in ethyl acetate, second order overall
BFirst order in ethyl acetate, first order overall
CZero order in ethyl acetate, zero order overall
DZero order in ethyl acetate, first order overall
Answer & Solution
Correct answer: D. Zero order in ethyl acetate, first order overall
1. Ethyl acetate does not appear in the rate law, so its exponent is zero.
2. Zero order means changing its concentration leaves the rate untouched.
3. Methanol appears to the first power, contributing one to the overall order.
4. The overall order is the sum of the exponents: 1 + 0 = 1, first order overall.
5. Reading the balanced equation instead of the rate law is what tempts the first order in ethyl acetate options.
_Source: OpenStax Chemistry (CC BY 4.0), Ch 12 "Kinetics", section 12.3 Rate Laws_
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