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What is the molarity of a solution holding 7.0 x 10^-3 mol of iodine, I2, in a total volume of 100.0 mL?
A0.70 M
B0.070 M
C7.00 M
D0.0070 M
Answer & Solution
Correct answer: B. 0.070 M
1. Convert the volume to litres: 100.0 mL = 0.1000 L.
2. Molarity is moles divided by litres: 7.0 x 10^-3 mol / 0.1000 L.
3. The result is 0.070 M.
4. Forgetting the mL to L conversion gives 0.0070 M, ten times too small.
_Source: OpenStax Chemistry (CC BY 4.0), Ch 3 "Composition of Substances and Solutions", section 3.3 Molarity_
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