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The lifetime risk of pancreatic cancer is about 1.28%. Let X ~ G(0.0128) count how many people you must ask until one says they have it. What are the mean and standard deviation of X?

Aμ ≈ 78, σ ≈ 77.62
Bμ ≈ 78, σ ≈ 1.28
Cμ ≈ 1.28, σ ≈ 77.62
Dμ ≈ 128, σ ≈ 77.62
Answer & Solution
Correct answer: A. μ ≈ 78, σ ≈ 77.62
1. μ = 1/p = 1/0.0128 ≈ 78.13, which rounds to about 78 people. 2. σ = sqrt((1/p)(1/p - 1)) = sqrt((78.125)(77.125)) ≈ 77.62. 3. So on average you would need to ask about 78 people, with a standard deviation near 77.62. 4. Option D misreads 1.28% as 128 rather than 0.0128, giving the wrong mean entirely. _Source: OpenStax Introductory Statistics (CC BY 4.0), Ch 4 "Discrete Random Variables", section 4.4 Geometric Distribution_
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