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A student randomly guesses on a 32-question multiple-choice exam where each question has three choices, so X ~ B(32, 1/3). Passing with more than 75% correct means getting more than 24 questions right. What does the calculator find for P(x>24)?

AIt is close to one, near certainty of guessing that well
BIt equals exactly 0.75, matching the passing threshold
CIt equals exactly one third, matching the guessing rate
DIt is very small, essentially zero for random guessing
Answer & Solution
Correct answer: D. It is very small, essentially zero for random guessing
1. Under random guessing, X ~ B(32, 1/3), so the expected number correct is only about 32/3 ≈ 10.7. 2. Getting more than 24 correct out of 32 by pure guessing is far above that expected count. 3. A binomial calculator confirms P(x>24) is extremely small, practically zero. 4. Options A, B, and D each assign the wrong scale to this rare-event probability. _Source: OpenStax Introductory Statistics (CC BY 4.0), Ch 4 "Discrete Random Variables", section 4.3 Binomial Distribution_
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