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The lifetime risk of pancreatic cancer is about 1.28%. For a random sample of 200 people, X ~ B(200, 0.0128) counts those who will develop it. What are the mean and standard deviation of X?

Aμ = 2.56, σ ≈ 2.56
Bμ = 2.56, σ ≈ 1.59
Cμ = 1.28, σ ≈ 1.59
Dμ = 200.0, σ ≈ 0.0128
Answer & Solution
Correct answer: B. μ = 2.56, σ ≈ 1.59
1. Apply μ = np: μ = (200)(0.0128) = 2.56. 2. Apply σ = sqrt(npq): σ = sqrt((200)(0.0128)(0.9872)) ≈ 1.5897, which rounds to 1.59. 3. So the expected count is 2.56 people with a standard deviation of about 1.59. 4. Option A repeats μ as if it were σ, and option D leaves n and p unmultiplied, so neither is correct. _Source: OpenStax Introductory Statistics (CC BY 4.0), Ch 4 "Discrete Random Variables", section 4.3 Binomial Distribution_
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