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A storm cloud sits 2 km above the ground, and the lower surface of the cloud spans about 2 km^2. Treating the cloud and the ground beneath it as a parallel-plate capacitor with C0 = epsilon_0 A / d, what is the approximate capacitance of this cloud-Earth system?
A9 x 10^-6 F
B1.8 x 10^-8 F
C9 x 10^-9 F
D9 x 10^-15 F
Answer & Solution
Correct answer: C. 9 x 10^-9 F
1. Treat the cloud's underside and the ground as the two plates of a capacitor, with A = 2 km^2 = 2 x 10^6 m^2 and d = 2 km = 2000 m.
2. C0 = epsilon_0 A / d = (8.85 x 10^-12 F/m)(2 x 10^6 m^2) / (2000 m).
3. This works out to 8.85 x 10^-9 F, which rounds to 9 x 10^-9 F.
4. A storm cloud is like a giant capacitor precisely because it splits into two oppositely charged regions, the cloud base and the ground, separated by an insulating layer of air.
_Source: OpenStax Physics (CC BY 4.0), Ch 18 "Static Electricity", section 18.5 Capacitors and Dielectrics_
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