That same 200 microfarad camera-flash capacitor uses a 0.010 mm thick sheet of nylon (dielectric constant kappa = 3.4) as its dielectric. Using C = kappa epsilon_0 A / d, what plate area is needed?

1. Rearranging C = kappa epsilon_0 A / d for area gives A = C d / (kappa epsilon_0). 2. The plate separation equals the sheet thickness: d = 0.010 mm = 1.0 x 10^-5 m. 3. A = (200 x 10^-6 F)(1.0 x 10^-5 m) / [(3.4)(8.85 x 10^-12 F/m)] = 66 m^2. 4. This area is far too large to fit inside a handheld camera, which is why real flash capacitors use more advanced constructions rather than a single flat nylon sheet. _Source: OpenStax Physics (CC BY 4.0), Ch 18 "Static Electricity", section Dielectrics_