A charged, disconnected capacitor has a dielectric slipped between its plates. Compared with the same capacitor with nothing between the plates and the same charge Q, how does the electric field between the plates change?

1. The dielectric's molecules polarize in the field, and their own small field opposes part of the original field between the plates. 2. This partial cancellation weakens the net electric field between the plates. 3. Because the charge Q is fixed once the battery is disconnected, only the field weakens, not the amount of charge stored. 4. Assuming the field stays the same, as in option A, ignores what polarization inside the dielectric actually does to the field. _Source: OpenStax Physics (CC BY 4.0), Ch 18 "Static Electricity", section Dielectrics_