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A 10 microfarad capacitor is to store 120 microcoulombs of charge. Using V = Q/C, what voltage battery is needed to charge it to this level?
A120 V
B0.12 V
C12 V
D1.2 V
Answer & Solution
Correct answer: C. 12 V
1. Capacitance relates charge and voltage through C = Q/V, which rearranges to V = Q/C.
2. V = (120 x 10^-6 C) / (10 x 10^-6 F) = 12 V.
3. A 12 V battery is an easy, ordinary voltage to buy for this job.
_Source: OpenStax Physics (CC BY 4.0), Ch 18 "Static Electricity", section 18.5 Capacitors and Dielectrics_
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