A parallel-plate capacitor has plates of area 1.00 m^2 separated by 0.0010 m, with nothing between the plates. Using C0 = epsilon_0 A / d, where epsilon_0 = 8.85 x 10^-12 F/m, what is its capacitance?

1. C0 = epsilon_0 A / d = (8.85 x 10^-12 F/m)(1.00 m^2) / (0.0010 m). 2. This works out to 8.85 x 10^-9 F, which rounds to 8.9 x 10^-9 F, or 8.9 nF. 3. Even a plate the size of a football field gives a fairly small capacitance without a dielectric, which is why real capacitors use extra tricks to boost C. _Source: OpenStax Physics (CC BY 4.0), Ch 18 "Static Electricity", section 18.5 Capacitors and Dielectrics_