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Two metal plates are charged so that one plate holds a magnitude of charge Q and the potential difference between the plates is V. How is the capacitance C of this arrangement defined?
AC = Q x V
BC = Q + V
CC = Q / V
DC = V / Q
Answer & Solution
Correct answer: C. C = Q / V
1. Capacitance measures how much charge a capacitor can hold per unit of voltage applied across it.
2. This ratio is written as C = Q / V.
3. Inverting, multiplying, or adding the two quantities instead, as in the other options, does not match this definition.
_Source: OpenStax Physics (CC BY 4.0), Ch 18 "Static Electricity", section Capacitors_
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