A charge moves through a uniform electric field of 2.0 N/C, aligned with the x-direction, from x = 5.0 m to x = 11 m. Using delta V = -E(x_f - x_i), what change in voltage does the charge experience?

1. In a uniform field, delta V = -E (x_f - x_i). 2. The displacement is x_f - x_i = 11 m - 5.0 m = 6.0 m. 3. delta V = -(2.0 N/C)(6.0 m) = -12 V, a change of 12 V in size. 4. Doubling the field value instead of multiplying it by the 6.0 m displacement gives the mismatched value in option A, which is the usual arithmetic slip here. _Source: OpenStax Physics (CC BY 4.0), Ch 18 "Static Electricity", section 18.4 Electric Potential_