How much energy must a hydrogen atom's electron absorb to jump from the ground state (n = 1) to the second orbital (n = 2)? Use En = -13.6 eV / n^2.

1. The ground state energy is E1 = -13.6 eV divided by 1 squared, which is -13.6 eV. 2. The second orbital's energy is E2 = -13.6 eV divided by 2 squared, which is -3.4 eV. 3. The energy absorbed is the final energy minus the initial energy: -3.4 minus (-13.6). 4. Subtracting gives 10.2 eV. 5. 3.4 eV and 13.6 eV are just the individual orbital energies, not the difference between them, and 6.8 eV does not match this subtraction. 6. So 10.2 eV is correct. _Source: OpenStax Physics (CC BY 4.0), Ch 22 "The Atom", section 22.1 The Structure of the Atom_