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Using the acceleration and mass of the Saturn V rocket at liftoff, what does the source say its engines' thrust was?
AAbout 6.16 times ten to the sixth newtons
BAbout 3.36 times ten to the fourth newtons
CAbout 3.36 times ten to the seventh newtons
DAbout 2.20 newtons of thrust force
Answer & Solution
Correct answer: C. About 3.36 times ten to the seventh newtons
1. Thrust is defined as the quantity (delta m over delta t) times v_e, with units of newtons.
2. Substituting the given fuel burn rate and exhaust velocity, thrust equals (1.40 times ten to the fourth kg/s)(2.40 times ten to the third m/s).
3. That multiplication gives 3.36 times ten to the seventh N.
4. 2.20 newtons is simply the numeric value of the acceleration in different units, not the thrust force, and the other two options are each off by several orders of magnitude.
_Source: OpenStax College Physics (CC BY 4.0), Ch 8 "Linear Momentum and Collisions", section 8.7 Introduction to Rocket Propulsion_
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