Enolase catalyses a dehydration reaction in the ninth step of glycolysis. What is the product?

1. Enolase makes 2-phosphoglycerate lose water from its structure, which is a dehydration reaction. 2. A double bond forms, raising the potential energy in the remaining phosphate bond. 3. The product of that step is phosphoenolpyruvate. 4. The raised energy is what lets the final step transfer that phosphate straight onto adenosine diphosphate. 5. 2-phosphoglycerate is the starting material here, not the product, so it cannot be the answer. _Source: OpenStax Biology (1st ed., CC BY 4.0), Ch 7 "Cellular Respiration", section 7.2 Glycolysis_