A solid sphere is placed on a horizontal surface with **initial linear velocity $v_0$ (forward) and zero angular velocity** (it spins-skids forward). Coefficient of friction $\mu$. The **final speed** when pure rolling sets in is:

Friction decelerates linear motion ($a = -\mu g$) and angularly accelerates spin ($\alpha = \mu g R/I = 5\mu g/(2R)$). Pure rolling when $v = R\omega$: $v_0 - \mu g t = R \cdot (5\mu g/(2R))\cdot t = (5/2)\mu g t$ ⇒ $v_0 = (7/2)\mu g t$ ⇒ $t = 2v_0/(7\mu g)$. $v_f = v_0 - \mu g t = v_0 - 2v_0/7 = 5v_0/7$.