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A rational number $\dfrac{p}{q}$ (in lowest terms) has a terminating decimal expansion if and only if the prime factorisation of $q$ is of the form

A$3^n \times 7^m$
B$2^n \times 3^m$
Cany product of primes
D$2^n \times 5^m$
Answer & Solution
Correct answer: D. $2^n \times 5^m$
1. A decimal terminates only when the denominator's primes are 2 and/or 5. 2. So $q$ must be of the form $2^n \times 5^m$ (n, m ≥ 0). 3. e.g. $3/8 = 3/2^3 = 0.375$ terminates, but $1/3$ does not. _Source: Karnataka SSLC (KSEEB) Class 10 Mathematics, Ch8 'Real Numbers', §8.4 (decimal expansions)_
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