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A **hollow sphere** ($I = \tfrac{2}{3}MR^2$) and a **solid sphere** of equal mass and radius roll without slipping with the same translational speed $v$. The ratio of their **total KE** (hollow : solid) is:
A$5:3$
B$25:21$
C$1:1$
D$3:2$
Answer & Solution
Correct answer: B. $25:21$
KE $= \tfrac{1}{2}Mv^2(1 + I/MR^2)$. Hollow: $\tfrac{1}{2}Mv^2 \cdot 5/3$. Solid: $\tfrac{1}{2}Mv^2 \cdot 7/5$. Ratio $= (5/3)/(7/5) = 25/21$.
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