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In the reaction $CuO + H_2 \rightarrow Cu + H_2O$, the substance that is reduced is
A$H_2$
B$CuO$
C$Cu$
D$H_2O$
Answer & Solution
Correct answer: B. $CuO$
1. Reduction is loss of oxygen. $CuO$ loses oxygen to become Cu, so **$CuO$ is reduced**.
2. $H_2$ gains oxygen to become water, so it is oxidised (it is the reducing agent).
3. Thus CuO is the oxidising agent and H₂ the reducing agent.
_Source: Karnataka SSLC (KSEEB) Class 10 Science, Ch1 'Chemical Reactions and Equations', §1.3 (redox)_
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