A uniform rod of length $L$ is suspended from one end. Its **time peri…

Question

A uniform rod of length $L$ is suspended from one end. Its **time period** for small oscillations is:

Accepted Answer

B. $2\pi\sqrt{2L/(3g)}$

**Compound (physical) pendulum:** $T = 2\pi\sqrt{I/(Mgd)}$.
Here $I = ML^2/3$ (about end), $d = L/2$.
$T = 2\pi\sqrt{(ML^2/3)/(Mg \cdot L/2)} = 2\pi\sqrt{2L/(3g)}$.

Answer

$2\pi\sqrt{L/g}$

Answer

$2\pi\sqrt{L/(2g)}$

Answer

$2\pi\sqrt{3L/(2g)}$

A uniform rod of length $L$ is suspended from one end. Its time period for small oscillations is:

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