alleryStart learning →By Gauss's law, the total electric flux through a closed surface enclosing a net charge $Q_{enc}$ is
A$Q_{enc}\,\varepsilon_0$
B$\dfrac{Q_{enc}}{\varepsilon_0}$
C$\dfrac{\varepsilon_0}{Q_{enc}}$
D$\dfrac{Q_{enc}}{4\pi\varepsilon_0}$
Answer & Solution
Correct answer: B. $\dfrac{Q_{enc}}{\varepsilon_0}$
1. Gauss's law: $\displaystyle\oint \vec{E}\cdot d\vec{A} = \dfrac{Q_{enc}}{\varepsilon_0}$.
2. The flux depends only on the **enclosed** charge, not on the shape or size of the surface or where the charge sits inside.
3. Charges outside the surface contribute zero net flux.
_Source: Samacheer Kalvi Class 12 Physics Vol.1, Unit 1 'Electrostatics', §1.6 (Gauss law) / Long Answer Q.11_
Keep practising Electromagnetism
Browse all Electromagnetism questions for Tamil Nadu HSC (Class 12), or explore more Physics topics.
Related questions
On the axial line of a short dipole the electric field is $E_a$, and on the equatorial linThe energy stored in a capacitor of capacitance $C$ charged to voltage $V$ (holding chargeA parallel-plate capacitor has capacitance $C$. If BOTH the plate area and the plate separAn equipotential surface is one on whichThe relation between the electric field and the electrostatic potential isIf the voltage across a capacitor is increased from $V$ to $2V$, thenPoints A and B are at potentials $+7\ V$ and $-4\ V$. The work done in moving 50 electronsTwo objects rubbed together acquire a charge of $50\ nC$ each. The number of electrons tra